A steel part weighing 4.68 kg is immersed in machine oil. Calculate the Archimedean force acting

A steel part weighing 4.68 kg is immersed in machine oil. Calculate the Archimedean force acting on this part. (Oil density 900kg / m3, steel density 7800kg / m3)

Initial data: m (weight of the steel part) = 4.68 kg.

Reference values: g (acceleration due to gravity) ≈ 10 m / s2; by condition ρm (oil density) = 900 kg / m3; ρс (steel density) = 7800 kg / m3.

You can calculate the Archimedean force that acts on the steel part taken using the formula: Fa = ρm * g * V = ρm * g * m / ρс.

Calculation: Fa = 900 * 10 * 4.68 / 7800 = 5.4 N.

Answer: An Archimedean force of 5.4 N acts on the steel part taken.



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