A steel part weighing 50 kg is lifted vertically upwards using a rope. The elastic force of the rope is 550H.

A steel part weighing 50 kg is lifted vertically upwards using a rope. The elastic force of the rope is 550H. Determine the acceleration of the part.

m = 50 kg.
g = 9.8 m / s ^ 2.
N = 550 N.
a -?
There are 2 forces acting on the steel part.
Gravity Ft directed vertically downward, rope tension force N directed vertically upward.
The force of gravity Ft is determined by the formula: Ft = m * g.
Let’s write 2 Newton’s law: m * a = N – m * g.
a = (N – m * g) / m.
a = (550 N – 50 kg * 9.8 m / s ^ 2) / 50 kg = 1.2 m / s ^ 2.
Answer: the acceleration of the steel part is a = 1.2 m / s ^ 2.