A steel part with a volume of 4 dm3 is located at a height of 2 m. Determine the potential energy of the part.

To find the potential energy of the steel part under consideration, we apply the formula: En = m * g * h = ρst * V * g * h.

Constant and variable values: ρst – steel density (ρst = 7800 kg / m3); V is the volume of the part (V = 4 dm3 = 4 * 10-3 m3); g – acceleration due to gravity (g ≈ 10 m / s2); h is the height of the steel part (h = 2 m).

Let’s perform the calculation: Ep = ρst * V * g * h = 7800 * 4 * 10-3 * 10 * 2 = 624 J.

Answer: The steel part must have a potential energy of 624 J.