A steel rod with a mass of 600 g was heated from 20 degrees to 1020 degrees. How much has the int. rod energy?

Problem data: m (weight of the steel bar taken) = 600 g (0.6 kg); t0 (temperature of the steel bar before heating) = 20 ºС; t (final temperature) = 1020 ºС.

Reference values: Cc (specific heat capacity of steel) = 500 J / (kg * K).

The increase in the internal energy of the steel bar taken is calculated by the formula: Q = Cc * m * (t – t0).

Calculation: Q = 500 * 0.6 * (1020 – 20) = 300 * 10 ^ 3 J (300 kJ).

Answer: The internal energy of the rod has increased by 300 kJ.