A steel splinter, falling from a height of 470 m, warmed up by 0.5 ° C as a result of the work of air resistance

| June 10, 2021 | education

A steel splinter, falling from a height of 470 m, warmed up by 0.5 ° C as a result of the work of air resistance forces. What is the velocity of the fragment near the surface of the Earth?

Data: h (height of fall of the steel fragment) = 470 m; Δt (change in the temperature of the fragment) = 0.5 ºС.

Constants: С (specific heat capacity of steel) = 500 J / (kg * ºС); g (acceleration due to gravity) = 9.81 m / s2.

The speed of the fragment at the surface of the Earth is determined from the equality: En = Q + Ek.

m * g * h = C * m * Δt + 0.5 * m * V ^ 2.

g * h = C * Δt + 0.5 * V ^ 2.

V ^ 2 = 2 * (g * h – C * Δt).

V = √ (2 * (g * h – C * Δt)) = √ (2 * (9.81 * 470 – 500 * 0.5)) ≈ 93.4 m / s.

Answer: The speed of the fragment at the surface is 93.4 m / s.



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