A steel tank weighing 500 g and with a capacity of 40 liters is filled with water and heated to 70 degrees.

| February 8, 2021 | education

A steel tank weighing 500 g and with a capacity of 40 liters is filled with water and heated to 70 degrees. How much heat was required for this. The initial temperature of the ox and the tank is 20 degrees.

Initial data: m (weight of the steel tank) = 500 g = 0.5 kg; V (volume of water in the tank) = 40 l (m2 (mass of water) = 40 kg); tн (initial temperature of the tank, water) = 20 ºС; tк (end temperature of the tank, water) = 70 ºС.

Constants: C1 (specific heat capacity of steel) = 500 J / (kg * K); C2 (specific heat capacity of water) = 4200 J / (kg * K).

Heat quantity: Q = Q1 (tank heating) + Q2 (water heating) = C1 * m1 * (tк – tн) + С2 * m2 * (tк – tн) = (tк – tн) * (C1 * m1 + C2 * m2) = (70 – 20) * (500 * 0.5 + 4200 * 40) = 8 412 500 J ≈ 8.4 MJ.



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