A stone falls from a 10 m high mountain without friction and air resistance.

A stone falls from a 10 m high mountain without friction and air resistance. At what height its kinetic energy becomes equal to its potential energy.

Problem data: h (the height of the mountain from which the given stone began to fall) = 10 m.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

Since a given stone, according to the condition, falls without friction and resistance, then, based on the law of conservation of energy, half of the potential energy of the stone will go into kinetic at 1/2 of the initial height.

Proof: En0 = 2En; m * g * h0 = 2 * m * g * h, whence h = h0 / 2 = 5 m (correct).

Answer: The stone will be at a height of 5 m.