A stone is thrown from a tower with a height of h = 49 in a horizontal direction with v0 = 5m / s.

A stone is thrown from a tower with a height of h = 49 in a horizontal direction with v0 = 5m / s. Determine at what distance s from the tower the stone fell to the ground

Ignoring the force of air resistance, the movement of the stone horizontally is uniform, and vertically – uniformly accelerated, with the acceleration of gravity g = 9.8 m / s2 directed vertically downward.

Equation of vertical movement of the stone:

h = gt ^ 2/2,

where h is the initial height, h = 49 m; t is the time of the fall of the stone, s.

t = (2 h / g) ^ 1/2 = (2 × 49 / 9.8) ^ 1/2 = 3.16 s.

Distance from tower s, at which the stone fell to the ground:

s = V0 t = 5 × 3.16 = 15.8 m.

Answer: s = 15.8 m.