A stone is thrown horizontally from a tower 45 meters high at a speed of 10 m / s.

| June 11, 2021 | education

A stone is thrown horizontally from a tower 45 meters high at a speed of 10 m / s. At what distance from the tower it will fall to the ground and what will be its speed at the moment of falling.

Data: h (tower height, stone path) = 45 m; Vg (horizontal speed of the stone) = 10 m / s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) The duration of the fall: S = h = g * t ^ 2/2, whence t = √ (2h / g) = √ (2 * 45/10) = 3 s.

2) Distance from the tower: L = Vg * t = 10 * 3 = 30 m.

3) Speed at the moment of falling: V = √ (Vv ^ 2 + Vg ^ 2) = √ ((g * t) ^ 2 + Vg ^ 2) = √ ((10 * 3) ^ 2 + 10 ^ 2) = √1000 = 31.62 m / s.

Answer: The stone will fall at a distance of 30 m from the tower and will have a speed of 31.62 m / s at the moment of falling.



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