A stone is thrown horizontally from a tower 60 meters high at a speed of 25 m / s.

A stone is thrown horizontally from a tower 60 meters high at a speed of 25 m / s. At what distance x from the base of the tower will it fall to the ground?

To determine the required distance from the base of the tower under consideration to the point where the stone falls, we apply the formula: X = Vg * t = Vg * √ (2h / g).

Values of variables and constants: Vg – horizontal speed of the stone (Vg = 25 m / s); h – tower height (h = 60 m); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: X = Vg * √ (2h / g) = 25 * √ (2 * 60/10) = 86.6 m.

Answer: The stone had to fall at a distance of 86.6 m from the base of the tower.



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