A stone is thrown horizontally from a tower with a height of h = 20 m at a speed of V0 = 15 m / s

A stone is thrown horizontally from a tower with a height of h = 20 m at a speed of V0 = 15 m / s. Find the time t of movement of the stone. At what distance S from the base of the tower and at what speed V will it fall to the ground?

Initial data: h (height of the considered tower) = 20 m; V0 (horizontal velocity of the stone) = 15 m / s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) Stone movement time: h = g * t ^ 2/2 and t = √ (2h / g) = √ (2 * 20/10) = 2 s.

2) Distance from the place of fall to the base of the tower in question: S = V0 * t = 15 * 2 = 30 m.

3) Falling speed: V = √ (Vv ^ 2 + V0 ^ 2) = √ ((g * t) ^ 2 + V0 ^ 2) = √ ((10 * 2) ^ 2 + 15 ^ 2) = 25 m /with.