A stone was thrown horizontally from a 30 m high tower. Find the potential energy of the stone 2 seconds after the start
| February 23, 2021 | education
A stone was thrown horizontally from a 30 m high tower. Find the potential energy of the stone 2 seconds after the start of the movement. Stone weight 0.2 kg. On the surface of the earth, potential energy is zero.
Data: h (tower height) = 30 m; t (fall time) = 2 s; m (stone mass) = 0.2 kg.
Constants: by condition g (acceleration of gravity) = 10 m / s2.
To calculate the desired value of the potential energy of the stone in 2 s, we use the law of conservation of energy: m * g * h = En1 + m * V ^ 2/2.
m * g * h = En1 + (g * t) ^ 2/2.
En1 = m * g * h – (g * t) ^ 2/2.
Calculation: En1 = 0.2 * 10 * 30 – (10 * 2) ^ 2/2 = 60 – 20 = 40 J.
Answer: After 2 s, the stone will have a potential energy of 40 J.
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