A stone was thrown horizontally from a tower 45 m high and fell to the ground at a distance
A stone was thrown horizontally from a tower 45 m high and fell to the ground at a distance of 18 m from the foot of the tower. Determine the speed imparted to the stone when thrown.
h = 45 m.
L = 18 m.
g = 10 m / s2.
t = 2 s.
V0 -?
Horizontally, the stone will move evenly, so the distance from the place where the stone fell to the tower L is expressed by the formula: L = V0 * t, where t is the time of flight of the stone.
V0 = L / t.
The stone will move vertically downward at uniform acceleration with the acceleration of gravity g, without the initial vertical component of the velocity.
h = g * t ^ 2/2.
t = √ (2 * h / g).
t = √ (2 * 45 m / 10 m / s2) = 3 s.
V0 = 18 m / 3 s = 6 m / s.
Answer: a stone was thrown from the tower horizontally at a speed of V0 = 6 m / s.