# A stone was thrown horizontally from a tower 45 m high and fell to the ground at a distance

**A stone was thrown horizontally from a tower 45 m high and fell to the ground at a distance of 18 m from the foot of the tower. Determine the speed imparted to the stone when thrown.**

h = 45 m.

L = 18 m.

g = 10 m / s2.

t = 2 s.

V0 -?

Horizontally, the stone will move evenly, so the distance from the place where the stone fell to the tower L is expressed by the formula: L = V0 * t, where t is the time of flight of the stone.

V0 = L / t.

The stone will move vertically downward at uniform acceleration with the acceleration of gravity g, without the initial vertical component of the velocity.

h = g * t ^ 2/2.

t = √ (2 * h / g).

t = √ (2 * 45 m / 10 m / s2) = 3 s.

V0 = 18 m / 3 s = 6 m / s.

Answer: a stone was thrown from the tower horizontally at a speed of V0 = 6 m / s.