A stone weighing 0.4 kg was thrown vertically upward at a speed of 20 m / s. What is the maximum height of the stone?

m = 0.4 kg.

g = 10 m / s2.

V0 = 20 m / s.

V = 0 m / s.

hmax -?

When climbing up, only gravity acts on the stone, so it will be slowed down with the acceleration of gravity g.

The height of the rise of the stone h is expressed by the formula: h = (V0 ^ 2 – V ^ 2) / 2 * g, where V0, V are the initial and final velocity of the stone, g is the acceleration of gravity.

At the maximum height hmax, the stone stops, its final speed V = 0 m / s, the formula will take the form: hmax = V0 ^ 2/2 * g.

hmax = (20 m / s) ^ 2/2 * 10 m / s2 = 20 m.

Answer: the stone will be able to rise to a maximum height of hmax = 20 m.