A stone weighing 0.5 kg fell from a certain height. The fall lasted 2s. Find the kinetic and potential energy of the stone

A stone weighing 0.5 kg fell from a certain height. The fall lasted 2s. Find the kinetic and potential energy of the stone at the moment when their values are equal. Neglect air resistance

First, we will find the height, and we will find the height using the formula
h = Vot + gt ^ 2/2, because our Vo is equal to 0, and the formula can be simplified to this form
h = gt ^ 2/2
Substitute values
h = 10 * 2 ^ 2/2 = 20 (m)
Thanks to the law of conservation of energy, we know the energy does not go anywhere and does not appear from empty space, we also know that the kinetic energy is maximum at the beginning of the throw, and potential at the end, and they will be equal halfway, that is, 10 m
Since they are equal, it will be more convenient to find the energy by the potential energy formula
Ep = mgh = 0.5 * 10 * 10 = 50 (J)
Answer: Ep = Ek = 50 (J)