A stone weighing 500 g falls from a height of 60 m without initial velocity. At what height will its impulse be equal to 15 kg • m / s?

Over the entire path, the body mass will not change in any way, so first we find the speed using the formula V = Vo + at, find the time and substitute it under the formula h = Vot + at ^ 2/2
Impulse (p) = 15, which means
15 = 0.5 * V
V = 30 (m / s)
Now we substitute the values into the second formula V = Vo + at
30 = 0 + 10 * t
t = 3 (c)
And now we just substitute the values of t into the formula h = Vot + at ^ 2/2
h = 0 * 3 + 10 * 3 ^ 2/2 = 45 (m)
Answer: h = 45 (m)