A straight conductor 0.5 m long is in a uniform magnetic field with an induction of 4 T. The conductor is located
A straight conductor 0.5 m long is in a uniform magnetic field with an induction of 4 T. The conductor is located at an angle of 60 ° to the vector B of the magnetic induction. What is the Ampere force acting on the conductor from the side of the magnetic field when the current in the conductor is 1 A.
L = 0.5 m.
B = 4 T.
∠α = 60 °.
I = 1 A.
Fump -?
A conductor with a current in a magnetic field is acted upon by the Ampere force Famp, the value of which is determined by the formula: Famp = I * B * L * sinα, where I is the current in the conductor, B is the magnetic induction of the field, L is the length of the conductor, ∠α is the angle between the direction of the current and the vector of magnetic induction B.
Famp = 1 A * 4 T * 0.5 m * sin60 ° = 1.732 N.
Answer: an Ampere force Famp = 1.732 N. acts on a straight conductor with a current in a magnetic field.