A straight conductor 0.8 m long, through which a current of 7 A flows, is in a uniform magnetic field.

A straight conductor 0.8 m long, through which a current of 7 A flows, is in a uniform magnetic field. The modulus of the magnetic induction vector is 0.3 T, the conductor is located at an angle of 30 to the vector B. The force acting on the conductor from the side of the magnetic field is equal to -?

L = 0.8 m.

I = 7 A.

B = 0.3 T.

∠α = 30.

Fump -?

A conductor with a current in a magnetic field is acted upon by the Ampere force Famp, the value of which is determined by the formula: Famp = I * B * L * sinα, where L is the length of the conductor, I is the current in the conductor, V is the magnetic induction of the field, ∠α is the angle between the direction of the current in the conductor and the vector of magnetic induction B.

sin30 = 0.5.

Famp = 7 A * 0.3 T * 0.8 m * sin30 = 0.84 N.

Answer: a magnetic field acts on a conductor with a current with an Ampere force Famp = 0.84 N.