A straight conductor 1 = 0.2 m long, through which a current I = 2 A flows, is in a uniform magnetic

| May 28, 2021 | education

A straight conductor 1 = 0.2 m long, through which a current I = 2 A flows, is in a uniform magnetic field with induction B = 6 T and is located at an angle of 30 ° to vector B. What is the force acting on the conductor from the side of the magnetic field ?

L = 0.2 m.

I = 2 A.

B = 6 T.

∠α = 30 °.

Fump -?

On a conductor of length L, in a magnetic field with induction B, through which an electric current with a current I flows, the Ampere force Famp acts, the value of which is expressed by the formula: Famp = I * L * B * sinα, where ∠ α is the angle between the direction of the current in the conductor and the magnetic induction of the field B.

Famp = 2 A * 0.2 m * 6 T * sin30 ° = 1.2 N.

Answer: the ampere force Famp = 1.2 N. acts on the conductor with current from the side of the magnetic field.



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