A straight conductor 1 = 0.2 m long, through which a current I = 2 A flows, is in a uniform magnetic
A straight conductor 1 = 0.2 m long, through which a current I = 2 A flows, is in a uniform magnetic field with induction B = 6 T and is located at an angle of 30 ° to vector B. What is the force acting on the conductor from the side of the magnetic field ?
L = 0.2 m.
I = 2 A.
B = 6 T.
∠α = 30 °.
Fump -?
On a conductor of length L, in a magnetic field with induction B, through which an electric current flows with a current strength I, the Ampere force Famp acts, the value of which is expressed by the formula: Famp = I * L * B * sinα, where ∠ α is the angle between the direction of the current in the conductor and the magnetic induction of the field B.
Famp = 2 A * 0.2 m * 6 T * sin30 ° = 1.2 N.
Answer: the ampere force Famp = 1.2 N. acts on the conductor with current from the side of the magnetic field.