A straight conductor 20 cm long, through which a current of 3A flows, is in a uniform magnetic

| April 27, 2021 | education

A straight conductor 20 cm long, through which a current of 3A flows, is in a uniform magnetic field with an induction of 4T and is located at an angle of 90 degrees to the magnetic induction vector. What is the force acting on the conductor from the side of the magnetic field?

According to Ampere’s law, the force that acts on the conductor is:
F = I * B * L * sin a, where I is the current strength (I = 3 A), B is the value of the magnetic field induction (B = 4 T), L is the length of the conductor (L = 20 cm = 0.2 m ), sin a is the angle between the vector of magnetic induction and the direction along which the current flows (sin a = sin 90 = 1, that is, the force will be maximum).
Hence:
F = I * B * L * sin a = 3 * 4 * 0.2 * 1 = 2.4 N.
Check: H = A * T * m = A * (kg * s ^ -2 * A ^ -1) * m = kg * m / s ^ 2 = N.
Answer: The current strength is 2.4 N.



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