A straight conductor l = 0.3m long, through which a current I = 12A passes, is placed in a uniform magnetic

A straight conductor l = 0.3m long, through which a current I = 12A passes, is placed in a uniform magnetic field with a magnetic induction of B = 0.5T. Determine the force acting on the conductor if it is located a) perpendicular to the field lines; b) along the lines of the field.

l = 0.3 m.

I = 12 A.

B = 0.5 T

∠α1 = 90.

∠α2 = 0.

Fump1 -?

Fump2 -?

A conductor with a current strength I of length l, in a magnetic field with induction B, acts on the Ampere force Famp, the value of which is determined by the formula: Famp = I * B * l * sinα, where ∠α is the angle between the direction of the current in the conductor and the vector of magnetic induction B.

Since in the first case the conductor is located perpendicular to the lines of force of the magnetic field ∠α1 = 90, then sin90 = 1.

Famp1 = I * B * l.

Famp1 = 12 A * 0.5 T * 0.3 m = 1.8 N.

In the second case, the conductor is located along the lines of force of the magnetic field ∠α2 = 0 or ∠α2 = 180, then sin00 = sin180 = 0.

If one of the factors is 0, then the whole product is 0: Famp2 = 0 N.

Answer: with the perpendicular arrangement of the conductor Famp1 = 1.8 N, when the conductor is located along, then the Ampere force Famp2 = 0 N does not act on it.