A straight conductor was placed in a uniform magnetic field perpendicular to the lines of magnetic induction

| September 1, 2021 | education

A straight conductor was placed in a uniform magnetic field perpendicular to the lines of magnetic induction, through which a current of 4 A flows. Determine the induction of this field if it acts with a force of 0.2 N for every 10 cm of the length of the conductor.

I = 4 A.

Famp = 0.2 N.

∠α = 90.

L = 10 cm = 0.1 m.

B -?

The ampere force Famp acts on the conductor through which the electric current pokes in a magnetic field, the value of which is determined by the formula: Famp = I * B * L * sinα, where I is the current in the conductor, B is the magnetic induction of the field, L is the active length conductor, ∠α is the angle between the direction of the current and the magnetic induction.

B = Famp / I * L * sinα.

B = 0.2 N / 4 A * 0.1 m * sin90 = 0.5 T.

Answer: the magnetic induction of the field in which the conductor is located is B = 0.5 T.



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