A straight conductor with a weight of 0.1 N is suspended horizontally on two thin wires. The central part of the conductor 0.5 m

A straight conductor with a weight of 0.1 N is suspended horizontally on two thin wires. The central part of the conductor 0.5 m long is in a uniform magnetic field with an induction of 0.1 T (the magnetic induction vector is directed vertically). At what angle from the vertical will the wires that support the conductor deviate if a current of 2 A is passed through it?

The weight of the body is in another way the force of gravity, it acts vertically downward, and the Ampere Force is the force of the magnetic field acting on the conductor with current. The Ampere force is equal to YBLsinA = Fa, and the angle between the current and the magnetic induction vector, hence the sine 90 = 1, which means the Ampere Force is 0.1N. Imagine a right-angled triangle, where the Ampere Force and the Weight of the body are its legs, through the trigonometric function – the tangent, we express the ratio of the sides, that is, 0.1H / 0.1H = tga, where tga = 1, this is equal to 45 degrees.
Answer: The wires will deviate from their normal position by 45 degrees.