A straight line is drawn through the point (-1; 1), parallel to the straight line y = 7x. Find the abscissa of the point

| June 24, 2021 | education

A straight line is drawn through the point (-1; 1), parallel to the straight line y = 7x. Find the abscissa of the point of intersection of this straight line with the Ox axis.

One straight line is parallel to the other if the angles of inclination to the coordinate axes of these straight lines coincide. The angle of inclination of the straight line determines the coefficient in front of X. Therefore, the equation of the desired straight line will have the form:

Y = 7X + A, where A is a certain numerical coefficient. We find it by substituting the coordinates of the point (- 1; 1) into the equation:

1 = 7 x (- 1) + A;

A = 1 + 7 = 8.

Straight line equation:

Y = 7X + 8.

Intersection with the 0X axis occurs when Y = 0:

0 = 7X + 8;

X = – 7/8 = – 0.875.

Answer: X = – 0.875.



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