A straight line is drawn through vertex A of parallelogram ABCD, which intersects side BC at point E
| March 16, 2021 | education
A straight line is drawn through vertex A of parallelogram ABCD, which intersects side BC at point E, and the extension of side DC at point F. Prove that triangles ABE and EFC are similar.
In triangles ABE and EFC, the angles CEF and AED are equal as the vertical angles formed by the intersection of lines BC and AF.
The angle ECF and ABE are equal as the criss-cross angles formed by the intersection of the secant DC of the parallel straight lines DF and AB.
Then the triangles ABE and EFC are similar in two angles, as required.
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