A straight line parallel to side AB of triangle ABC intersects side AC at point M
| March 10, 2021 | education
A straight line parallel to side AB of triangle ABC intersects side AC at point M, and side BC at point K. Prove that the angles of triangle MCК are equal to the angles of triangle ABC.
The angle at the vertex C of the triangle is common, the angle ACD = MCK.
The angles CAB and CMC are equal as the corresponding angles at the intersection of parallel straight lines AB and MK of the secant AC.
Angle CAB = CMK.
The angles CBA and CKM are equal as the corresponding angles at the intersection of parallel straight lines AB and MK of the secant BC.
Angle CBA = CKM.
Q.E.D.
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