A straight wire 0.40 m long moves in a uniform magnetic field at a speed of 5.0 m / s perpendicular to the induction lines.

A straight wire 0.40 m long moves in a uniform magnetic field at a speed of 5.0 m / s perpendicular to the induction lines. The potential difference between the ends of the wire is 0.6 V. Determine the magnetic induction.

L = 0.4 m.

V = 5 m / s.

∠α = 90.

U = 0.6 V.

IN – ?

Let us write down Faraday’s law of electromagnetic induction: U = ΔF / t.

The voltage at the ends of the conductor U is directly proportional to the rate of change in the magnetic flux ΔF.

ΔФ = Δ (B * S) * cosβ = B * ΔS * cosβ, where ∠β is the angle between the perpendicular to the plane of motion of the conductor and the vector of magnetic induction B. ∠β = ∠α – 90 = 90 – 90 = 0.

ΔS = L * Δd, where Δd is the distance the conductor has moved.

We write the speed of movement of the conductor V with the formula: V = Δd / t

U = B * L * Δd * cos00 / t = B * L * V.

B = U / L * V.

B = 0.6 V / 0.4 m * 5 m / s = 0.3 T.

Answer: the magnetic induction of the field in which the conductor moves is B = 0.3 T.