A stretched spring with a rigidity of 100 Newtons per meter acts on a body attached

A stretched spring with a rigidity of 100 Newtons per meter acts on a body attached to it with a force of 25 Newtons. What is the potential energy of the spring?

To calculate the potential energy of the spring used, we apply the formula: En = k * Δx ^ 2/2 = k * (F / k) ^ 2/2 = F ^ 2 / 2k.

The values of the variables: F – the force with which the used spring acts on the body attached to it (F = 25 N); k is the stiffness of the spring (k = 100 N / m).

Let’s perform the calculation: En = 25 ^ 2 / (2 * 100) = 3.125 J.

Answer: The potential energy of the spring used is 3.125 J.



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