A student, standing on the ice, throws a 2 kg briefcase horizontally away

A student, standing on the ice, throws a 2 kg briefcase horizontally away from him at a speed of 3 m / s. How fast and in what direction will the student move? Student weight 50 kg

To find the student’s speed after discarding the portfolio, we apply the law of conservation of momentum: mп * Vп + mу * Vу = 0, whence Vу = -mp * Vп / mу, therefore, the student and the portfolio move in opposite directions.

Variables: mp – portfolio weight (mp = 2 kg); Vp – portfolio throwing speed (Vp = 3 m / s); mу is the mass of the student (mу = 50 kg).

Calculation: Vу = mп * Vп / mу = 2 * 3/50 = 0.12 m / s.

Answer: The student will start moving at a speed of 0.12 m / s in the direction opposite to the movement of the discarded portfolio.



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