A sulfuric acid solution was added to a solution containing 20.8 g of barium chloride. Find the mass of precipitated salt?

The equation for the reaction of barium chloride with sulfuric acid:

BaCl2 + H2SO4 = BaSO4 + 2HCl

The amount of substance BaCl2:

v (BaCl2) = m (BaCl2) / M (BaCl2) = 20.8 / 208 = 0.1 (mol).

According to the reaction equation, from 1 mol of BaCl2, 1 mol of BaSO4 is formed, therefore:

v (BaSO4) = v (BaCl2) = 0.1 (mol).

Thus, the mass of the formed precipitate of barium sulfate:

m (BaSO4) = v (BaSO4) * M (BaSO4) = 0.1 * 233 = 23.3 (g).