A swimming pool with an area of 100 m ^ 2 is filled with water to a depth of 2 m. It is required to pump

A swimming pool with an area of 100 m ^ 2 is filled with water to a depth of 2 m. It is required to pump this water to a height of 3 m (counting from the surface of the water in the pool). Determine the work to be done while doing this.

Water pumping work:
A = Fd * h, Fd is the acting force (Fd = Ft = m * g, m is the mass of the raised water (m = ρ * V, ρ is the density of water (ρ = 1000 kg / m³), V is the volume of the pool (V = S * h1, where S is the area of the pool (S = 100 m2)), h1 is the water depth (h = 2 m), g is the acceleration of gravity (g = 10 m / s ^ 2))), h is the height rise of water (h = 3 m).
Let’s calculate the work:
A = Fd * h = m * g * h = ρ * V * g * h = ρ * S * h1 * g * h = 1000 * 100 * 2 * 10 * 3 = 6,000,000 J = 6 MJ.
Answer: To pump water, it is necessary to perform work equal to 6 MJ.