A tank moving at a speed of 36 km / h stumbles upon an anti-tank hedgehog, which makes it move with a constant

A tank moving at a speed of 36 km / h stumbles upon an anti-tank hedgehog, which makes it move with a constant acceleration ax = -50 m / s2. At what distance from the collision site the tank will stop.

Initial data: V (speed of the tank before collision with the anti-tank hedgehog) = 36 km / h (10 m / s); a (constant acceleration of the tank after a collision) = -50 m / s2; V (final tank speed) = 0 m / s.

The distance from the collision site at which the tank will stop is determined by the formula: S = (V ^ 2 – V0 ^ 2) / 2a.

Calculation: S = (0 – 10 ^ 2) / (2 * (-50)) = 1 m.

Answer: The tank will stop at a distance of 1 m after colliding with the anti-tank hedgehog.