A team of dogs can pull the sled in the snow with a force of 0.5 kN. What is the maximum weight

A team of dogs can pull the sled in the snow with a force of 0.5 kN. What is the maximum weight of the sleigh if the coefficient of friction between the runners and the snow is 0.1?

Given:

F thrust = 0.5 kN = 500 Newton – the force with which a team of dogs can pull the sled over the snow;

k = 0.1 is the coefficient of friction between the sleigh and the snow;

g = 9.8 Newton / kilogram – acceleration of gravity.

It is required to determine m (kilogram) – the maximum possible mass of the sleigh.

The movement of the sleigh on the snow is possible when the traction force exceeds the friction force. In the maximum possible case, they will be equal (the sled will move evenly at a constant speed). Then:

F friction = F thrust;

k * m * g = F thrust;

m = Fthrust / (k * g) = 500 / (0.1 * 9.8) = 500 / 0.98 = 510.2 kilograms.

Answer: the maximum possible weight of the sleigh is 510.2 kilograms.