A team of dogs dragging a sled along a horizontal path 10 km long does the work of 980 Kjoules

A team of dogs dragging a sled along a horizontal path 10 km long does the work of 980 Kjoules, counting a friction coefficient of 0.02 find the mass of the sled

To determine the value of the mass of the sleigh moved by a team of dogs, we will use the formula (the movement of the sleigh will be considered uniform): A = F * A = Ftr * S = μ * m * g * S, whence we express: m = A / (μ * g * S).

Variables and constants: A – the work of a team of dogs (A = 980 kJ = 980 * 10 ^ 3); μ – coefficient of friction (μ = 0.02); g – acceleration due to gravity (g ≈ 9.8 m / s2); S – the path of the team (S = 10 km = 104 m).

Calculation: m = A / (μ * g * S) = 980 * 10 ^ 3 / (0.02 * 9.8 * 10 ^ 4) = 500 kg.

Answer: The weight of the sled is 500 kg.