A thin homogeneous rod l = 2m long lies on the surface of the Earth. What is the mass
| September 23, 2021 | education
A thin homogeneous rod l = 2m long lies on the surface of the Earth. What is the mass of the rod if the minimum work that needs to be done to put the rod vertically is A = 750J.
Problem data: L (length of a thin homogeneous rod) = 2 m; Δh (change in the height of the center of mass of the rod) = 0.5L; A (minimum work to set the rod vertically) = 750 J.
Reference values: g (acceleration due to gravity) ≈ 10 m / s2.
The mass of the rod can be expressed from the formula: A = ΔEp = m * g * Δh = m * g * 0.5L, whence m = 2A / (g * L).
Calculation: m = 2 * 750 / (10 * 2) = 75 kg.
Answer: The mass of a thin homogeneous rod is 75 kilograms.
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