A tourist climbs a mountain at a speed of 2 km / h and then descends back at a speed of 6 km / h
| May 23, 2021 | education
A tourist climbs a mountain at a speed of 2 km / h and then descends back at a speed of 6 km / h. What is the average speed of a tourist along the way?
To determine the average speed of the tourist under consideration during the ascent and descent from the mountain, we use the formula: Vav = S / (tp + tc) = S / (S / 2Vp + S / 2Vc) = 1 / (1 / 2Vp + 1 / 2Vc).
Variables: Vп – speed of ascent up the mountain (Vп = 2 km / h); Vс – speed of descent (Vс = 6 km / h).
Calculation: Vav = 1 / (1 / 2Vp + 1 / 2Vc) = 1 / (1 / (2 * 2) + 1 / (2 * 6)) = 3 km / h.
Answer: When going up and down the mountain, the tourist in question moved at an average speed of 3 km / h.
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