A tourist left point A at a speed of 6 km / h and at the same time a tourist came to meet him

| May 5, 2021 | education

A tourist left point A at a speed of 6 km / h and at the same time a tourist came to meet him from point B – 2. By the time they met, the 1st had covered a distance of 1 + 1/3 more than the 2nd. How many hours later did they meet, if the distance AB = 21 km?

To solve this problem, we introduce a conditional variable “X”, through which we denote the distance traveled by the second tourist before meeting the first tourist. Then, according to the condition of the problem, we get X + 4X / 3 = 21 or 7X / 3 = 21 or X / 3 = 3 or X = 9 kilometers. Consequently, the first tourist traveled a distance equal to 4×9 / 3 = 12 kilometers before meeting the second tourist. Then, applying the speed formula, we get the time equal to 12 kilometers divided by 6 kilometers per hour. As a result, we get a time of 2 hours.
Answer: 2 hours.



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