A tourist sitting in a boat dropped a 200 g metal mug into the water. Diving with constant acceleration

A tourist sitting in a boat dropped a 200 g metal mug into the water. Diving with constant acceleration, the mug overcame a two-meter depth in 2 seconds and ended up at the bottom. Determine the resultant forces acting on the mug during its immersion.

Data: m (mass of the metal circle) = 200 g = 0.2 kg; t (duration of immersion of the circle on the bottom) = 2 s; h (depth, path of the circle) = 2 m.

To determine the resultant of the forces acting on the metal mug during immersion, we apply Newton’s second law: Fр = m * a = m * V / t = m * (2h / t) / t = m * 2h / t ^ 2.

Let’s perform the calculation: Fр = 0.2 * 2 * 2/2 ^ 2 = 0.2 N.

Answer: A resultant force of 0.2 N. acted on the metal mug.