A tourist with a total area of shoe soles S = 300 cm2 carries a backpack weighing m = 10 kg on his back.

| June 19, 2021 | education

A tourist with a total area of shoe soles S = 300 cm2 carries a backpack weighing m = 10 kg on his back. Determine the mass of a tourist if, being at rest, he creates a pressure on the surface of p = 25 kPa.

The pressure of a tourist with a backpack is the ratio of the force with which the mass of a tourist with a backpack presses on the ground to the value of the area of the soles of the shoes.
P = F / S, where P is the pressure of a tourist with a backpack on the ground (P = 25 kPa = 25 * 10 ^ 3 Pa); F is the pressure force (F = Ft = m * g, where m = m1 + m2, m1 is the mass of the tourist, m2 is the mass of the backpack (m2 = 10 kg), g is the acceleration of gravity (g = 10 m / s ^ 2 )), S-area of the soles (S = 300 cm ^ 2 = 300 * 10 ^ -4 m ^ 2).
P = F / S = m * g / S = (m1 + m2) * g / S.
m1 = P * S / g-m2 = (25 * 10 ^ 3) * (300 * 10 ^ -4) / 10-10 = 75-10 = 65 kg.
Answer: The mass of the tourist is 65 kg.



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