A toy with a mass of 200 g, moving from a state of rest, passes with an equally accelerated motion

A toy with a mass of 200 g, moving from a state of rest, passes with an equally accelerated motion of a fetter of 1 m in a time equal to 4 s. Determine the resultant of the forces acting on it.

These tasks: m (the mass of the toy in question) = 200 g (in SI m = 0.2 kg); S (the path traveled by the toy) = 1 m; t (duration of movement) = 4 s; uniformly accelerated motion.

To determine the resultant force acting on the toy in question, we use the formula (Newton’s second law): F = m * a = m * 2S / t2.

Let’s calculate: F = 0.2 * 2 * 1/4 ^ 2 = 0.025 N.

Answer: A resultant force of 0.025 N acted on the toy in question.