A train having 10 m / s moves with an acceleration of 5 m / s ^ 2, how long does it take to reach 16 m / s?

Given: V0 (speed of the train under consideration before acceleration) = 10 m / s; a (acceleration) = 5 m / s2; V (the speed that the train must develop) = 16 m / s.

The duration of acceleration of the train under consideration to a speed of 16 m / s is determined by the formula: t = (V – V0) / a.

Calculation: t = (16 – 10) / 5 = 6/5 = 1.2 s.

Answer: The train in question will accelerate to 16 m / s in 1.2 s.