A train, moving evenly at a speed of 63 km / h, passes a pedestrian walking in the same direction parallel to the tracks
| December 8, 2020 | education
A train, moving evenly at a speed of 63 km / h, passes a pedestrian walking in the same direction parallel to the tracks at a speed of 3 km / h in 57 seconds. Find the length of the train in meters.
S = v * t
It is very important that the train and the person head in the same direction. If a person were standing, then the speed of the train relative to him would be 63 km / h. However, a person also walks, he has a speed of 3 km / h, then the train moves relative to him at a speed of 63-3 = 60 km / h
Now let’s convert km / h to m / s
60 * 1000/3600 = 60,000 / 3600 = 600/36 = 100/6 m / s
Now let’s multiply time by speed:
100/6 * 57 = 5700/6 = 950 m.
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