A train weighing 10 tons in 1 minute increased its speed from 54 to 74 km / h

A train weighing 10 tons in 1 minute increased its speed from 54 to 74 km / h Find the traction force if the drag coefficient is 0.003

Given: m (train mass) = 10 t (in SI m = 10 * 10 ^ 3 kg); t (duration of speed change) = 1 min (in SI t = 60 s); V0 (initial speed) = 54 km / h (in SI V0 = 15 m / s); V (final speed) = 74 km / h (in SI V = 20.556 m / s); μ (coefficient of resistance to movement) = 0.003.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

Traction force of a given train: F = m * a + Fsopr. = m * ((V – V0) / t) + μ * m * g.

Let’s calculate: F = 10 * 10 ^ 3 * ((20.556 – 15) / 60) + 0.003 * 10 * 10 ^ 3 * 10 = 1226 N.