A train weighing 1800 tons, departs from the station moving at uniform acceleration. Disregard movement resistance.

| April 29, 2021 | education

A train weighing 1800 tons, departs from the station moving at uniform acceleration. Disregard movement resistance. The work of the traction force of the locomotive on the path of 1 km in the first 100 s of movement is …

Data: m (train weight) = 1800 t (in SI m = 1.8 * 10 ^ 6 kg); V0 (initial speed) = 0 m / s; S (distance traveled) = 1 km (in SI S = 1 * 10 ^ 3 m); t (duration of the train under consideration) = 100 s.

To calculate the work of the traction force of the locomotive, we apply the formula: A = ΔEk = m * V ^ 2/2 – m * V0 ^ 2/2 = m * (2S / t) ^ 2/2 – 0 (the speed is expressed from the formula: S = (V + V0) * t / 2).

Calculation: A = 1.8 * 10 ^ 6 * (2 * 1 * 10 ^ 3/100) ^ 2/2 = 360 * 10 ^ 6 J (360 MJ).

Answer: The work of the traction force is 360 MJ.



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