A train weighing 500 tons moved at a speed of 10 m / s. Under the influence of a braking force of 125 kN

| March 8, 2021 | education

A train weighing 500 tons moved at a speed of 10 m / s. Under the influence of a braking force of 125 kN, it stopped. determine what distance the train traveled to the stop.

m = 500 t = 500,000 kg.

V = 10 m / s.

Ftor = 125 kN = 125000 N.

S -?

Let’s use the law of conservation of energy. At the beginning of deceleration, the total energy of the train consisted only of the kinetic energy of motion Ek, which is determined by the formula: Ek = m * V ^ 2/2, where m is the mass of the train, V is the speed of movement.

During braking, the force Ftor performs work A, the value of which is determined by the formula: A = Ftor * S.

The change in kinetic energy is equal to the work of the braking force: Ek = A.

m * V ^ 2/2 = Ftor * S.

The braking distance will be determined by the formula: S = m * V ^ 2/2 * Ftor.

S = 500,000 kg * (10 m / s) ^ 2/2 * 125,000 N = 200 m.

Answer: the braking distance of the train was S = 200 m.



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