A train weighing 500 tons, moving in a straight line, increases its speed from 60 km / h

A train weighing 500 tons, moving in a straight line, increases its speed from 60 km / h to 80 km / h. What kind of work does the pulling force do?

Initial data: m (train weight) = 500 t (500 * 10 ^ 3 kg); the train is moving in a straight line; Vн (initial train speed) = 60 km / h (16.67 m / s); V2 (train speed after acceleration) = 80 km / h (22.22 m / s).

The work performed by the traction force is determined by the formula: A = F * S = m * a * ((V ^ 2 – V0 ^ 2) / 2a) = m * (V ^ 2 – V0 ^ 2) / 2.

Let’s make the calculation: A = 500 * 10 ^ 3 * (22.22 ^ 2 – 16.67 ^ 2) / 2 ≈ 54 * 1 ^ 06 J (54 MJ).

Answer: The pulling force did the work at 54 MJ.