A train with a mass of 150 tons, under the action of a force of 150 kN, began to slow down.

A train with a mass of 150 tons, under the action of a force of 150 kN, began to slow down. Determine the initial speed of the train, if after braking it covered a distance of 500 m?

Data: m (train mass) = 150 t (in SI m = 150 * 10 ^ 3 kg); F (acting braking force) = 150 kN (150 * 10 ^ 3 N); S (distance traveled by the train after the start of braking) = 500 m.

To calculate the initial speed of the train under consideration, we apply the formula: S = V0 ^ 2 / 2a, whence V0 = √ (2a * S) = √ (2 * (F / m) * S).

Calculation: V0 = √ (2 * (150 * 10 ^ 3 / (150 * 10 ^ 3)) * 500) = √1000 = 31.62 m / s.

Answer: Before the start of braking, the speed of the train in question was 31.62 m / s.