A train with a mass of 2000 tons, when braking with an acceleration of 0.3 m / s2

A train with a mass of 2000 tons, when braking with an acceleration of 0.3 m / s2, stopped 50 s after the start of braking. How much heat is generated during braking?

Data: m (train mass) = 2000 t (in SI m = 2 * 10 ^ 6 kg); a (acceleration during deceleration) = 0.3 m / s2; t (deceleration time) = 50 s.

To calculate the heat that was released when braking a given train, we apply the formula: A = Q = ΔEk = 0.5 * m * V2 = 0.5 * m * (a * t) 2.

Let’s calculate: Q = 0.5 * 2 * 10 ^ 6 * (0.3 * 50) ^ 2 = 225 * 10 ^ 6 J (225 MJ).

Answer: When a given train was decelerated, 225 MJ of heat was released.



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