A train with a mass of kg departs from the station with uniform acceleration and at a distance of 250 m

A train with a mass of kg departs from the station with uniform acceleration and at a distance of 250 m develops a speed of 36 km / h. Resistance coefficient 0.006. Determine the traction force of the locomotive.

Data: m (train weight) = 10 ^ 5 kg; V0 (initial speed) = 0 m / s; uniformly accelerated motion; S (distance traveled) = 250 m; V (speed reached by the train) = 36 km / h (in SI V = 10 m / s); μ (drag coefficient) = 0.006.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

To calculate the traction force of a locomotive, we use the equality: m * a = Ft – Fcopr, whence Ft = m * a + Fcopr = m * (V ^ 2 / 2S) + μ * m * g.

Calculation: Ft = 10 ^ 5 * (10 ^ 2 / (2 * 250)) + 0.006 * 10 ^ 5 * 10 = 26 * 10 ^ 3 N (26 kN).

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